Write an algebric expression for 16 subtracted from the product of consecutice number is 56
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Let the first number be n
Then the second number is n+1
The product is n×(n+1)=56
⇒n2+n−56=0
Known: 7×8=56. However the equation's 56 is nagetive, so one of the 7 and 8 is negative.
The equation has +n so the larger of the two is positive. Giving:
(n−7)(n+8)=0
⇒n=+7 and n=−8
As a first number n=−8 is not logical so the first number is n=7
Thus the second number is 8.
Then the second number is n+1
The product is n×(n+1)=56
⇒n2+n−56=0
Known: 7×8=56. However the equation's 56 is nagetive, so one of the 7 and 8 is negative.
The equation has +n so the larger of the two is positive. Giving:
(n−7)(n+8)=0
⇒n=+7 and n=−8
As a first number n=−8 is not logical so the first number is n=7
Thus the second number is 8.
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