Write an algorithm to calculate the total
number of advertisements that will be
displayed from the batch.
Input
The input consists of an integer - batch,
representing the batch of advertisements,
Output
Print an integer representing the total number
of advertisements that will be displayed by the
media company.
Constraints
0 < batch <= 10^9
Answers
Answer:
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Answer:
The algorithm is as follows :
Explanation:
# include<stdio.h>
#include<stdlib.h>
/*
Constraints 0 < batchs 109?
*/
#define MIN 0
#define MAX 109
main()
{
int Batch_of_Advertisements=-1;
int a, b, c;
int No_of_Advt=0;
while(Batch_of_Advertisements<MIN || Batch_of_Advertisements>MAX)
{
printf("\n\tEnter the Batch of Advertisements (%d to %d): ",MIN,MAX);
scanf("%d",&Batch_of_Advertisements);
}
if(Batch_of_Advertisements <10 && Batch_of_Advertisements%2==0)
{
No_of_Advt=Batch_of_Advertisements;
}
if(Batch_of_Advertisements >9 && Batch_of_Advertisements<100)
{
a = Batch_of_Advertisements/10;
b = Batch_of_Advertisements%10;
if(a%2==0) No_of_Advt = No_of_Advt + a;
if(b%2==0) No_of_Advt = No_of_Advt + b;
}
if(Batch_of_Advertisements >99)
{
a = Batch_of_Advertisements/100;
b = (Batch_of_Advertisements%100)/10;
c = (Batch_of_Advertisements%100)%10;
if(a%2==0) No_of_Advt = No_of_Advt + a;
if(b%2==0) No_of_Advt = No_of_Advt + b;
if(c%2==0) No_of_Advt = No_of_Advt + c;
}
printf("\n\tNo. of advertisements = %d",No_of_Advt);
}
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