Question

Write an algorithm to check whether a
number is an Armstrong number or not ?​​

Answer 1

Algorithm

Input the number.

Initialize sum=0 and temp=number.

Find the total number of digits in the number.

Repeat until (temp != 0)

remainder = temp % 10.

result = resut + pow(remainder,n)

temp = temp/10.

if (result == number)

Answer 2

Answer:

Step 1: START

Step 2: INPUT N

Step 3: SET SUM=0,D=N

Step 4: REM= N%10

Step 5: SUM= SUM+(REM*REM*REM)

Step 6: N=N/10

Step 7: REPEAT STEPS 4 TO 6, UNTIL N>0

Step 8: IF SUM=D

PRINT “NUMBER IS ARMSTRONG”

ELSE

PRINT “NUMBER IS NOT ARMSTRONG”

Step 9: STOP