Write an algorithm to find reverse of an integer
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Algorithm:
Here input number is: num
(1) Initialize rev_num = 0
(2) Loop while num > 0
(a) Multiply rev_num by 10 and add remainder of num
divide by 10 to rev_num
rev_num = rev_num*10 + num%10;
(b) Divide num by 10
(3) Return rev_num
I was first writing the program but then i saw algorithm written at top in your question.
Once you know the program the algorithm can be made easily and vice-versa.
Hope this helps :)
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