write an algorithm to find whether a given number is odd or even
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An algorithm to find whether a given number is odd or even:
- Step 1: Start
- Step 2: Taking input of a number say n
- Step 3: Read the number n
- Step 4: Check if((n%2)==1), then
Print n is an odd number
Else
Print n is an even number
- Step 5: End
What are odd and even numbers?
- Odd numbers are the numbers that are not divisible by 2, it starts from 1. In other words, these numbers leave 1 as a remainder.
- Even numbers are the numbers that are divisible by 2, it starts from 0. In other words, these numbers leave 0 as a remainder.
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Even integers can always be divided into two without leaving any remaining pieces. They have a 0, 2, 4, 6, or 8 digit ending. Odd numbers are not equally divided by 2.
Algorithm to find whether a given number is odd or even :
- Even integers can always be divided into two without leaving any remaining pieces. They have a 0, 2, 4, 6, or 8 digit ending. Odd numbers are not equally divided by 2.
- After division by an integer, the remaining operation, percent, returns the residual. If n is even, n percent 2 == 0 will indeed be true, but if n is odd, it will also be incorrect.
ALGORITHM :
STEP 1: START
STEP 2:Receive data from a user or dynamically assign value.
STEP 3: if num percent 2 == 0. Even Integer should be printed.
STEP 4: Else, Print an Odd Number
STEP 5: Print an Odd Number
STEP 6: END
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