Question

write an algorithm to print perfect numbers between 1 to 100​

Answer 1

Answer:

For example: 6 is Perfect Number since divisor of 6 are 1, 2 and 3. Sum of its divisor is

1 + 2+ 3 =6

and 28 is also a Perfect Number

since 1+ 2 + 4 + 7 + 14= 28

Other perfect numbers: 496, 8128

Program is written using C++

Explanation:

#include <iostream>  

#include <cctype>

using namespace std;  

int main(){

   int n,i=1,sum=0;

   cout << "Enter a number: ";

   cin >> n;

      while(i<n){

      if(n%i==0)

      sum=sum+i;

      i++;  

}

 

if(sum==n)

   cout << i << " is a perfect number\n";  

else

   cout << i << " is not a perfect number\n";

   system("pause");  

return 0;

}

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