Question

write an
algoritum to find
find the sum
of all number between I to 100​

Answer 1

Explanation:

Program to print all abundant numbers between 1 and 100

The abundant number can be called an excessive number and defined as the number for which the sum of its proper divisors is greater than the number itself.

A first abundant number is the integer 12 having the sum (16) of its proper divisors (1,2,3,4,6) which is greater than itself(12).

Examples: 12, 18, 20, 24, 30, 36

In this program, we have to find all abundant numbers between 1 and 100.

Algorithm

STEP 1: START

STEP 2: DEFINE n, i, j

STEP 3: SET sum =0

STEP 4: SET n =100

STEP 5: REPEAT STEP 6 to STEP 10 UNTIL i<=n

STEP 6: REPEAT STEP 7 and STEP 8 UNTIL j<=i/2

STEP 7: if i%j ==0

STEP 8: sum =sum + j

STEP 9: if sum>i then PRINT i+

STEP 10: SET sum=0

STEP 11: END

Answer 2

Answer:

Hello friend's

Explanation:

Algorithm

STEP 1: START

STEP 2: DEFINE n, i, j

STEP 3: SET sum =0

STEP 4: SET n =100

STEP 5: REPEAT STEP 6 to STEP 10 UNTIL i<=n

STEP 6: REPEAT

STEP 7 and STEP 8 UNTIL j<=i/2

STEP 7: if i%j ==0

STEP 8: sum =sum + j

STEP 9: if sum>i then PRINT i+

STEP 10: SET sum=0

STEP 11: END

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