Question

write an alp to count number of 0's in a given 8 bit number and display result in screen by storing the result in a variable

Answer 1

Answer:

Explanation:

Algorithm –

Convert the decimal number in Accumulator to its binary equivalent

Rotate the digits of the binary number right without carry

Apply a loop till count is not zero to change the values of D register and count

Copy the value of D register to accumulator and store the result

Program –

MEMORY ADDRESS MNEMONICS COMMENTS

2000 MVI B 75 B ← 75

2002 MVI C 08 C ← 75

2004 MVI D 00 D ← 00

2006 MOV A, B A ← B

2007 RRC Rotate right without carry

2008 JNC 200C Jump if Not Carry

200B INR D D ← D+1

200C DCR C C ← C-1

200D JNZ 2007 Jump if Not Zero

2010 MOV A, D A ← D

2011 STA 3050 A → 3050

2014 HLT Stops execution

Explanation –

MVI B 75 moves 75 decimal number into B register

MVI C 08 moves 08 decimal number into C register, which is taken as counter as the number is of 8 bites

MVI D 00 moves 00 number into d register

MOV A, B moves the contents of B register into A (accumulator) register

RRC rotates the contents of A (which is 75 with binary equivalent 01110101) right

JNC 200C jumps to 200C address and perform the instructions written there if the carry flag is not zero

INR D increases the value of D register by adding one to its contents

DCR C decreases the value of C register by subtracting one from its contents

JNZ 2007 jumps to 2007 address and perform the instructions written there if the zero flag is not zero

MOV A, D moves the contents of B register into A register

STA 3050 store the contents of A at 3050 memory location

HLT stops execution

Answer 2

Answer:

The following python program counts the number of zeroes in a given 8-bit number and displays the result:

count = 0

number = input()

if(len(number)==8):

for i in number:

   if(i=='0'):

     count+=1

print(count)

 

else:

 print("Invalid number")

Explanation:

• Initially, the count variable's value is zero.
• Then we take the input from the user and check whether the number has 8-bits or not.
• If the number is less than or greater than 8-bit then we print an invalid number message.
• Otherwise, we iterate over the number and check whether the bit of the number is equal to zero or not.
• If the bit is equal to zero then we increase the value of count by 1.
• Lastly, we print the count as our final output.

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