Question

write an AP whose a = 4 and d = 2.5.​

Answer 1

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• a = 4 and d = 25

• a1 = 4

• a2 = a1 + d = 4 + 25 = 29

• a3 = a2 + d = 29 + 25 = 53

• a4 = a3 + d = 53 + 25 = 78

• a5 = a4 + d = 78 + 25 = 103

• a6 = a5 + d = 103 + 25 = 128

Hence , the A.P is 4 , 29 , 53 , 78 , 103 , 128 ....

........ Hope it helps ......

Answer 2

Answer:

t1=4 & t2=2.5

t2-t1=2.5-4= -1.5

t3-t2=-1.5-2.5= -4

t4-t3= -4 - 1.5= -1.5

therefore 2.5,-1.5,-4.-1.5

it is ap