Question

Write an ap whose first term is 9 and common difference is 4

Answer 1

Answer:

9,13,17,21,25

Step-by-step explanation:

hope it helps you

Answer 2

Answer:

• 9, 13, 17, 21, 25, ... ... , 5 + 4n.

Solution:

We know that,

$\blue\bigstar\boxed{\red{T_n = a+(n-1)d}}$

Where,

• Tn = nth term
• a = 1st term
• n = Number of terms
• d = Common difference

So, here we have 1st term(a) and common difference(d). We can find A.P using formula.

1st term = 9 + (1-1)4 = 9 + 0 = 9.

2nd term =  9 + (2-1)4 = 9 + (1)4 = 13.

3rd term =  9 + (3-1)4 = 9 + (2)4 = 17.

4th term = 9 + (4-1)4 = 9 +(3)4 = 21.

5th term = 9 +(5-1)4 = 9 +(4)4 = 25.

So on...

nth term = 9 + (n-1)4 = 9 + 4n - 4 = 5 + 4n.

Therefore,

AP will be 9, 13, 17, 21, 25, ... ... , 5 + 4n.