Math, asked by ghodakegautama, 2 months ago

write an ap whose first termis nine and common difference is five​

Answers

Answered by shubhamugale2005
0

a = 9 d = 3

a + d = 9 + 3 =12

a + 2d = 9 + 2(3)

= 15

a+ 3d = 9 + 3(3)

= 18

a + 4d = 9 + 4(3)

= 21

:. the required A. P. is 9, 12 , 15 ,18 , 21

Answered by meghakharbikar05
1

write an ap whose first termis nine and common difference is five

a=9d =3

a+d=9+3=12

a+2d=9/+2(3)

=15

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