write an arithmetic sequence with 30 as the sum of first three terms
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Step-by-step explanation:
sum(5) = (5/2)(2a + 4d) = 30
2a + 4d = 12
a + 2d = 6
a = 6-2d
so we can assign any value to d
e.g. d = 7
then a = 6-14 = -8
one possible sequence is:
-8 , -1, 6, 13, 20
(their sum is 30)
let d = 3
a = 6-6 = 0
terms are:
0, 3, 6, 9, 12
(their sum is 30)
Hope its help. .
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