Question

Write an arithmetic sequence with algebraic expression 2n+3

Answer 1

Answer:

Tn=2n+3

⇒Tn−1=2(n−1)+3

=2n−2+3=2n+1

∴Tn−Tn−1=(2n+3)−(2n+1)=2

which does not depend on 'n'.

Therefore, the difference of two consecutive terms is constant.

⇒ Given progression is an arithmetic progression.

Step-by-step explanation:

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Answer 2

Answer:

Answer

Given, arithmetic sequence X

n

=5n+3

a. The first term of the sequence, put n=1

X

1

=5×1+3=8

b. d=5 (coefficient of n be the common difference)

The remainder divide by 5=3.

(

5

8

=3,

5

13

=3,

5

18

=3,etc)