Question

write an arithmetic sequence with common difference 6 find its 12th terms

Answer 1

Answer:

term and the common difference of the arithmetic progression? What is its 19th term?

6th and 12th terms of an arithmetic progression are 15 and 27 respectively.

Hence,

t6 =15

t12 =27

Let a be the first term and d be the common difference respectively.

nth term = a+(n-1)d

t6 = a+(6–1) d

15 = a+5d ———(1)

t12 = a+(12–1) d

27 = a+11 d ———(2)

Subtracting (1) From (2) ,

d=2

a=5

19th term = a+(19–1)d = 5+ (18 x 2) = 41

Ans:

First term is 5

The common difference is 2

19th term is 41.