Question

Write an arithmetic sequence with first term 8 and common difference 3. b) Check whether 100 is a term of this sequence? What about 1001?

Answer 1

Answer:

First term of the sequence is 10 and common difference is 3. Thus, first three terms of the sequence are 10, 13 and 16. Let 100 be the nth term of the sequence. ... Therefore, 100 is the 31st term of the sequence.

Answer 2

Step-by-step explanation:

First term of the sequence is 10 and common difference is 3.

a1 = 10 and d = 3

Next term = a2=a1+d=10+3=13

a3=a2+d=13+3=16

Thus, first three terms of the sequence are 10, 13 and 16.

Let 100 be the nth term of the sequence.

an=a1+(n−1)d

100=10+(n−1)3

90=(n−1)3

n−1=30

n=31, which is a whole number.

Therefore, 100 is the 31st term of the sequence.