Question

Write an elgebibraic expression for the sequence of natural numbers which leave reminder 1 on division by 5

Answer 1

Step-by-step explanation:

First term is 1 because it leaves remainder 1 on division by 5.

Common difference is 5 because 5 is the number by which it is divided. The divisor will be the common difference.

First term - Common difference

= 1 - 5 = - 4

∴ A. E. = dn + (f - d)

= 5n - 4

Any term in the form 5n-4 leaves remainder 1 on division by 5.

Let's check.

5x 1 - 4 = = 1

5 x 2 - 4 = 6

5 x 3 - 4= 11

So the sequence is 1, 6, 11,16......

These terms leave remainder 1 on division by 5.

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