Question

write an equation and graph the following.
A line passing though (2,5) and perpendicular to the line
whose equation is 4y - 2x+7=0.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

What is the equation of the line parallel to 2x + 4y +7 = 0 and through the point (3,2)?

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Isaac Asaase

Answered 2 years ago

Equation:2x+4y+7=0……eqn(1)

Point (3,2)

Formula for the equation of a line is

Y-y1=m(x-x1) where m is the gradient of the line and x1 and y1 is the x and y coordinates respectively

Let find the gradient(slop) of eqn(1) by making y the subject

4y=-2x-7

Y=-2x/4–7/4

Y=-1/2x-7/4

Therefore the gradient(slop) of eqn(1) is 1/2

Now since it is parallel to the equation given then there slop will be equation

Therefore using the gradient -1/2 And the point (3,2),Let put it into the formula and solve for the equation

y-y1=m(x-x1)….x1=3,y1=2,m=-1/2

y-2=-1/2(x-3)…multiply through by the denominator which is 2

2(y-2)=2×-1/2(x-3)

2y-4=-x+3,Let equate it to zero

x+2y-4-3=0

x+2y-7=0

Therefore the equation of the line is

x+2y-7=0