Math, asked by freddythebest124, 4 hours ago

Write an equation for the line parallel to y=5x+11y=5x+11 that passes through the point P(7,2).

Answers

Answered by Anonymous
2

There is a second line that passes through the point (1,2) and is parallel to the line given above. What is the equation of this second line?

Possible Answers:

y=34x+2.75

y=34x+1.25

y=−34x+1.25

y=34x+2.625

y=−34x+2.75

Correct answer:

y=−34x+2.75

Explanation:

Parallel lines have the same slope. Solve for the slope in the first line by converting the equation to slope-intercept form.

3x + 4y = 12

4y = –3x + 12

y = –(3/4)x + 3

slope = –3/4

We know that the second line will also have a slope of –3/4, and we are given the point (1,2). We can set up an equation in slope-intercept form and use these values to solve for the y-intercept.

y = mx + b

2 = –3/4(1) + b

2 = –3/4 + b

b = 2 + 3/4 = 2.75

Plug the y-intercept back into the equation to get our final answer.

y = –(3/4)x + 2.75

Answered by ItzYrSnowy
1

Answer:

Step-by-step explanation:

There is a second line that passes through the point (1,2) and is parallel to the line given above. What is the equation of this second line?

Possible Answers:

y=34x+2.75

y=34x+1.25

y=−34x+1.25

y=34x+2.625

y=−34x+2.75

Correct answer:

y=−34x+2.75

Explanation:

Parallel lines have the same slope. Solve for the slope in the first line by converting the equation to slope-intercept form.

3x + 4y = 12

4y = –3x + 12

y = –(3/4)x + 3

slope = –3/4

We know that the second line will also have a slope of –3/4, and we are given the point (1,2). We can set up an equation in slope-intercept form and use these values to solve for the y-intercept.

y = mx + b

2 = –3/4(1) + b

2 = –3/4 + b

b = 2 + 3/4 = 2.75

Plug the y-intercept back into the equation to get our final answer.

y = –(3/4)x + 2.75

Similar questions