Question

write an equation for the line that contains (-2,1) and is perpendicular to 4x-2y=8

Answer 1

Answer:

$x = - 2y$

Step-by-step explanation:

$required \: line \: \: \: \: \: \: \: \: 2x + 4y = p \\ \\( - 2 \: \: \: \: \: \: \: \: \: 1) \: \: \: \: \: \: \: passes \: through \: \: \: above \: \: \: line \: \: \: \\ \\ \\ 2( - 2) + 4(1) = p \\ \\ - 4 + 4 = p \\ \\ p = 0 \\ \\ \\ then \: \: \: \: equation \: is \: \: \: 2x + 4y = 0 \\ \\ \\ 2x = - 4y \\ \\ x = - 2y$