Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(-5,-2); y=-4x+4
Write an equation for the line in slope-intercept form.
(Simplify your answer. Use integers or fractions for any numbers in the equation.)
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Step-by-step explanation:
First, you put the equation into the standard “slope/intercept” form.
4x -y = 2 subtract 4x from both sides ; -y = -4x + 2 Multiply by -1 :
y = 4x - 2
In this standard form we see that the slope of the line (coefficient of x) is 4. ANY line parallel to this one must thus also have a slope of 4.
y = 4x - a (generic)
ANY other combination of slope multiples and constant terms will therefore also be lines parallel to this one. The one that passes through a specific point will simply have a different constant term.
We find this by putting our point value into the equation:
3 = 4(-2) + a ; 3 = -8 + a ; a = 11
Thus, our “parallel line equation” through the point (-2,3) is:
y = 4x + 11
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Answer:(-5,-2); y=-4x+4Write an equation for
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