Question

Write an equation in slope-intercept form that goes through the points (-3,5) and (6,-7)

Answer 1

Answer:

6y+12x+6=0

or

6y+12x = -6

Step-by-step explanation:

Given points : (-3,5) and (6,-7)

therefore,

x1 = -3 y1 = 5

x2 = 6 y2 = -7

From the equation of a slope

$\frac{y - y1}{x - x1} = \: \frac{y2 - y1}{x2 - x1} \\ substitute \: the \: values \\ \frac{y - 5}{x - - 3} = \: \frac{ - 7 - 5}{6 - - 3} \\ \frac{y - 5}{x + 3} = \: \frac{ - 7 - 5}{6 + 3} \\ \frac{y - 5}{x + 3} = \: \frac{ - 12}{9} \\ cross \: multiplication \\ 6(y - 5) \: = \: - 12(x + 3) \\ 6y - 30 \: = \: - 12x - 36 \\ collect \: like \: terms \\ 6y + 12x - 30 + 36 = 0 \\ 6y + 12x + 6 = 0 \\ or \\ 6y + 12x = - 6$

Thanks❤ , hope it helps

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