Write an equation of a line parallel to line EF in slope-intercept form that passes through the point (2, 6).
Answers
Given :- The equation of line EF is y = 1 over 2 x + 6. Write an equation of a line parallel to line EF in slope-intercept form that passes through the point (2, 6).
Solution :-
we have,
→ Equation of line EF = (1/2)x + 6 .
The given equation is slope-intercept form where the general form is,
- y = mx + b.
- where m is the slope and the y-intercept is b.
From the equation we get,
- m = 1/2 .
- b = 6.
Now, we know that,
- The slope of the parallel lines is equal .
So,
→ Slope of equation is also = (1/2).
Thus, using the slope-point form of the forming the equation,
- y - y₁ = m(x - x₁)
Substituting the given values,
→ y - 6 = (1/2)(x - 2)
→ 2y - 12 = x - 2
→ 2y - x = - 2 + 12
→ 2y - x = 10
→ 2y = (10 + x)
→ y = (1/2)[10 + x]
→ y = (x/2) + 5 . (Ans.)
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