Question

Write an equation of a line that passes through the point (8, 4) and is parallel to the line y = 4x + 2.

Answer 1

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In Attachment

Answer 2

Answer:

y - 4x + 28 = 0

Step-by-step explanation:

If a line is parallel to another line, slope of both the lines will be same. Steepness of both lines is equal.

Slope of a line is given by, y = mx + c where m is the slope.

So the slope of line y = 4x + 2 is 4.

Now we have the information that a line which has a slope of 4 and passes through the point (8,4) and we have to find it's equation.

Using slope point form of straight line,

⇒ y - y1 = ( x - x1 ) m

Here,

x1 and y1 are the points through which the given line passes.

m is the slope.

By substituting the known values in equation, we get :

⇒ y - 4 = ( x - 8 ) ( 4 )

⇒ y - 4 = 4x - 32

⇒ y - 4 - 4x + 32 = 0

⇒ y - 4x + 28 = 0

This is the required equation.

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