Question

write an equation of the line has slope -2/3and passes through the points (6,2)​

Answer 1

Answer:

The general equation of line in 2d is given by y=mx+c

where m is slope of the line and c is y intercept of the line

we have m=-2/3, so the equation will be

y=-2/3x+c

Now, the given equation passes through (6,2) so the equation must satisfy these points i.e.

2=-2/3×6+c

c=6

so the required eqaution of line is y=-2/3x+6