Question

Write an equation of the line in slope-intercept form that is perpendicular to 4x + 8y = 16 and passes through (-5, 7)

Answer 1

short trick for perpendicular line is constant of A and B inter changed and opposit sign will replaced the given sign ex 4x+8y=16 eqn's perpendicular line is 8x-4y= lemda and than put the given point in this eqn -5,7 we get the value of lemda. and answer will be 8x-4y+68=0 ...