Write an equation of the line that passes through the given points.
1). (0 , -6) (3 , 9)
2). (4 , 1) (0 , 2)
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Answer:
Step-by-step explanation:
first point: given slope m=Y2-Y1/X2-X1 (BY USING TWO POINT FORM TO FIND OUT THE SLOPE)
second step: let Y2=9,Y1=-6,X2=3,X1=0
thirs step we know the equation to find the slope : Y-Y1=M(X-X1)
m=9-(-6)/3-0
m=9+6/3
m=15/3=5 slope=m=5
equation of line will be = Y-(-6)=5(X-0)
Y+6=5x
hence equation of straight line = 5X-Y-6=0
first point ; do the same for the given solution in the above step
let Y2=2,Y1=1,X2=0,X1=4
equation of staright line will be Y-1=2-1/0-4*(X-4)
Y-1=(-1/4)X-4
4Y-4=4-X
X+4Y-8=0
HENCE equation of staright line will be = X+4Y-8=0
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