Question

Write an equation of the line that passes through the points (−3,−4) and (0,2).
y= [ ]

Answer 1

$\tt \: Equation \: of \: line \: passing \: through \: points \: (x_1 , y_1) \: and \: (x_2 , y_2) :$

$\boxed{\tt \large \longrightarrow y - y_1 = x-x_1\bigg( \dfrac{y_2-y_1}{ x_2-x_1} \bigg )}$

$\tt \rightarrow \: here \: \bigg( \dfrac{y_2-y_1}{ x_2-x_1} \bigg ) is \: slope \: of \: line.$

Now , we have to find out the equation of the line that passes through the points (−3,−4) and (0,2).

$\tt \large \implies y -(- 4 )= x-(-3)\bigg( \dfrac{2-(-4)}{ 0-(-3)} \bigg )$

$\tt \large \implies y + 4 = x+3 \bigg( \dfrac{2+4}{ 3} \bigg )$

$\tt \large \implies y + 4 = x+3 \bigg( \dfrac{6}{ 3} \bigg )$

$\tt \large \implies y + 4 = x+3 \bigg( \dfrac{2}{ 1} \bigg )$

$\tt \large \implies y + 4 =2( x+3)$

$\tt \large \implies y + 4 =2 x+6$

$\tt \large \implies y -2x =6-4$

$\tt \large \implies y -2x =2$

$\tt \large \implies y -2x -2=0$

Answer :

$\large \bf y -2x -2=0$