Question

Write an equation that is perpendicular to the line y = 5x - 1 and passes through the point (10, 8)

Answer 1

Answer:

given line , y-5x+1=0

5x-y-1=0

slope=-a/b=5 , points=(10,8)

if two lines are perpendicular

m1.m2=-1

m2=-1/5

equn of line =(x-x1)=m(y-y1)

: (x-10)= -1/5(y-8)

5x-50=-y+8

5x+y-50-8=0

5x+y-58=0