Write an experiment to measure length, breadth and thickness of a glass block/
using meter rule. ( each reading correct to mm ). Taking the mean of three
readings in each case. Calculate the volume of the block. Using any convenient
balance gm and kg. Also calculate the density of the glass in SI unit using mass
and volume in the respective units. don't spam plzz and no irrelevant answers
Answers
Answer:
The length, breadth and thickness of a block are measured with the help of a meter scale. given ℓ =(5.12 + 0.01)cm, b =(10.15 +0.01)cm, t=(5.28+0.01)cm. The percentage error in volume is: soory i found related
Explanation:
Given that,
Length of the block l=(5.12+0.01)cm
Breadth of the block b=(10.15+0.01) cm
Thickness of the block t=(5.28+0.01) cm
We know that,
Relative error in volume of cuboid
V
dV
=
l
dl
+
b
db
+
t
dt
V
dV
=
5.12
0.01
+
10.15
0.01
+
5.28
0.01
V
dV
=
512
1
+
1015
1
+
528
1
Now, the percentage error in volume
V
ΔV
×100=0.48
%ΔV=0.48%
Hence, the percentage error in volume is 0.48.
Answer:
Answer:
The length, breadth and thickness of a block are measured with the help of a meter scale. given ℓ =(5.12 + 0.01)cm, b =(10.15 +0.01)cm, t=(5.28+0.01)cm. The percentage error in volume is: soory i found related
Explanation:
Given that,
Length of the block l=(5.12+0.01)cm
Breadth of the block b=(10.15+0.01) cm
Thickness of the block t=(5.28+0.01) cm
We know that,
Relative error in volume of cuboid
V
dV
=
l
dl
+
b
db
+
t
dt
V
dV
=
5.12
0.01
+
10.15
0.01
+
5.28
0.01
V
dV
=
512
1
+
1015
1
+
528
1
Now, the percentage error in volume
V
ΔV
×100=0.48
%ΔV=0.48%
Hence, the percentage error in volume is 0.48.