Question

write an expresion for the distance x covered in time t by a body which is initially rest and starts moving at a constant accleration a​

Answer 1

Answer:

Let,  

distance be  s,

acceleration be  a,  

time taken be t  ,

initial velocity u=0

Using the second equation of motion and substituting the above values we get,

S=ut+1/2 at∧2    

Since u=0 here, equation becomes;

S=1/2 at∧2

Answer 2

Let,

distance be

′x′

acceleration

′a′

time taken ′t '

initial velocity u=0

We know that distance can be expressed as:

X=ut+1/2 at

Since u=0 here, equation becomes;

=1/2 at

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