Question

Write an expression for distance covered in nth second for uniformly accelerated motion.​

Answer 1

Explanation:

ok

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Answer 2

Answer:

Let the uniform acceleration be p and for convenience, let the initial velocity be u .

Then , using s

n

=u+

2

1

a(2t−1)

We have , a=u−

2

p

+px

b=u−

2

p

+py

c=u−

2

p

+pz

a(y−z)+b(z−x)+c(x−y)=pxy−pxz+pyz−pxy+pxz−pxy=0

Explanation:

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