Write an expression for resistivity of a conductor and explain each term .
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Define the term electrical resistivity of a material. Write the S.I units. Derive an expression for the resistivity of a metal in terms of number density and mass of free electrons present in it .

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Solution :
Electrical resistivity of a material of a conductor is the resistance offered by unit length and unit area of cross section of a wire of the material .
Its S.I unit is ΩmΩm
The drift velocity of free electron in a conductor is
Vd=eVmeVd=eVme
But I=VdenAI=VdenA
Substituting for VdVd we get,
I=(evml)I=(evml)ρnA=e2VInAmlρnA=e2VInAml
V=I(mlne2tA)V=I(mlne2tA)
By Ohm's law V=IRV=IR
∴IR=I(mlne2TA)∴IR=I(mlne2TA)
R=mlne2TAR=mlne2TA
Also R=ρlAR=ρlA
Where ρρ is the resistivity of the material.
∴ρA=mlne2TA∴ρA=mlne2TA
=> ρ=mne2T
Questions >> CBSE XII >> Physics >> Current Electricity

Next similar question
Q)
Define the term electrical resistivity of a material. Write the S.I units. Derive an expression for the resistivity of a metal in terms of number density and mass of free electrons present in it .

A)
Need homework help? Click here.
Solution :
Electrical resistivity of a material of a conductor is the resistance offered by unit length and unit area of cross section of a wire of the material .
Its S.I unit is ΩmΩm
The drift velocity of free electron in a conductor is
Vd=eVmeVd=eVme
But I=VdenAI=VdenA
Substituting for VdVd we get,
I=(evml)I=(evml)ρnA=e2VInAmlρnA=e2VInAml
V=I(mlne2tA)V=I(mlne2tA)
By Ohm's law V=IRV=IR
∴IR=I(mlne2TA)∴IR=I(mlne2TA)
R=mlne2TAR=mlne2TA
Also R=ρlAR=ρlA
Where ρρ is the resistivity of the material.
∴ρA=mlne2TA∴ρA=mlne2TA
=> ρ=mne2T
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