Question

write an ionic equation for the reaction at the positive electrode.

Answer 1

Explanation:

The half equation is: Cu2+ + 2e- → Cu The hydroxide ion is more reactive than the sulphate ion, therefore this forms water (H2O) and oxygen at the positive electrode.

Answer 2

▪︎The half equation is: Cu2+ + 2e- → Cu The hydroxide ion is more reactive than the sulphate ion, therefore this forms water (H2O) and oxygen at the positive electrode.

▪︎ Write the ionic equation by breaking all the soluble ionic compounds (those marked with an (aq)) into their respective ions. Each ion should be shown with its charge and an (aq) to show that it is present in solution. Use coefficients to show the number of each ion present.