Question

Write an program to implement months to days like -- users can input months number and program can show the number of days
With Switch case
No C program

Answer 1

This is a C++ program:
#include<iostream.h>
#include<conio.h>
void main()
{
int monthno,ch;
cout<<"Month to days calculation";
cout<<"Enter the month's number";
cin>>monthno;
switch(ch)
{
case 1:
if(monthno=1)
{
cout<<"January=31days";
}
break;
case 2:
if(monthno=2)
{
cout<<"February=28days";
}
break;
case 3:
if (monthno=3)
{
cout<<"March=31days";
}
break;
case 4:
if(monthno=4)
{
cout<<"April=30days";
}
break;
case 5:
if(monthno=5)
{
cout<<"May=31days";
}
break;
case 6:
if(monthno=6)
{
cout<<"June=30days";
}
break;
case 7:
if(monthno=7)
{
cout<<"July=31days";
}
break;
case 8:
if(monthno=8)
{
cout<<August=31days";
}
break;
case 9:
if(monthno=9)
{
cout<<September=30days";
}
break;
case 10:
if (monthno=10)
{
cout<<"October=31days";
break;
case 11:
if (monthno=11)
{
cout<<"November=30days";
}
break;
case 12:
if(monthno=12)
{
cout<<"December=31days";
}
break;
default:
cout<<"Enter the right choice";
break;
getch();
}

Answer 2

Answer:

Program in C++

==============

#include <iostream>

using namespace std;

void main(){

int no_of_month, no_of_days;

int leap_test;

   //Birupaksha Nath

printf("Enter the no. of the month:\t");

scanf("%d",&no_of_month);

printf("\n\n");

 

switch(no_of_month){

   case 1:

   case 3:

   case 5:

   case 7:

   case 8:

   case 10:

   case 12:

   no_of_days=31;

       break;

   case 4:

   case 6:

   case 9:

   case 11:

       no_of_days=30;

       break;

   case 2:

       printf("Is it leap year?\n\tPress 1 for YES\n\tPress 0 for NO\n");

       scanf("%d",&leap_test);

       if(leap_test==1){

           no_of_days=29;

       }

       else{

           no_of_days=28;

       }

       break;

   default:

       no_of_days=0;

       break;

}

printf("\nThe month has %d days.\n\n\n",no_of_days);

}

Explanation: