Math, asked by anshika445734, 11 months ago

write an Pythagorean triplet whose smallest number is 8​

Answers

Answered by Anonymous
2

Answer:

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Answered by BrainlySteveJobs
0

Answer :

We get the Pythagorean triplets by using the General Formula that is [ 2m, m² - 1, n² + 1 ]

First let's take → m² - 1 = 8

→ m² = 8 + 1 = 9

→ m = 3

→ 2m = 6 and m² + 1 = 10

The triplet is therefore 6, 8, 10. hence, 8 is not the smallest method of this.

→ 2m = 8

→ m = 4

→ m² - 1 = 16 - 1 = 15 and

→ m² + 1 = 16 + 1 = 17

The triplet is 8, 18, 17 with 8 as the smallest number.

Similar example for this question:

Question:

Find a Pythagorean triplet in which one member is 12.

Answer :

if we take → m² - 1 = 12

→ m² = 12 + 1 = 13

So, the value of n will not be an integer.

now let's try → m² + 1 = 12

m² = 11 will not give an integer value for m.

→ 2m = 12

→ m = 6

→ m² - 1 = 36 - 1 = 35 and

→ m² + 1 = 36 + 1 = 37

Therefore, the required triplet are 12, 35, 37.

General Note:

All the Pythagorean triplets may not be obtained using this form.

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