Write an Pythagorean triplet whose smallest number is8
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Answered by
2
Required pythagorean Triplet is 8, 15, 17
Verification :-
8^2 = 64
15^2 = 225
17^2 = 289
=> 8^2 + 15^2 = 64 + 225
=> 8^2 + 15^2 = 289
=> 8^2 + 15^2 = 17^2
Verification :-
8^2 = 64
15^2 = 225
17^2 = 289
=> 8^2 + 15^2 = 64 + 225
=> 8^2 + 15^2 = 289
=> 8^2 + 15^2 = 17^2
Answered by
1
2m=8
m=8÷2
m=4
= m square - I = (4) square - I = 16-1= 15
=m square + I = (4) square + 1 = 16 + I = I7
. : the Pythagorean triplet of 8 is
[8,15,17]
m=8÷2
m=4
= m square - I = (4) square - I = 16-1= 15
=m square + I = (4) square + 1 = 16 + I = I7
. : the Pythagorean triplet of 8 is
[8,15,17]
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