Question

Write and balance the equation chlorine + sulphur dioxide +water gives sulphuric acid + hydrogen chloride

Answer 1

Balanced equation for reaction between chlorine, Sulphur and water

• The given word equation for the reaction is:

Chlorine + Sulphur dioxide + Water $\rightarrow$ Sulfuric acid + Hydrogen chloride.

• When the chemical equation for the above reaction is written it gives:

$Cl_2+SO_2+H_2O\rightarrow H_2SO_4+HCl$

• For the above equation when the number of atoms for the reactant side is calculated it gives:

Cl = 2

S = 1

H = 2

O = 3

• When the number of atoms for the product side is calculated it gives:

Cl = 1

S = 1

H = 3

O = 4

• The obtained result indicates that the chlorine, hydrogen and oxygen atoms are not equal on both sides. Thus the reaction is not balanced.
• The balanced reaction has the number of atoms involved in reaction in reactants as well as the product as equal.
• To make both side equal some changes must be made as shown in the balanced equation is:

$Cl_2+SO_2+2H_2O\rightarrow H_2SO_4+2HCl$

• For the above equation, the number of atoms in the reactant is:

Cl = 2

S = 1

H = 4

O = 4

• The number of atoms in product is:

Cl = 2

S = 1

H = 4

O = 4

• As the number of atoms in the reactants side is equal to the number of atoms in the product side, the reaction is balanced.

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Answer 2

Answer:Cl2+So2+2H2O=H2SO4+2HCl

Explanation: