Write and derive the 3 equations of motion
Answers
This is the answer for the given question. ..
Hai guys,
there are totally three types of motions equations , they are ,
.v = u + at
.v^2=u^2+2 as
.s=ut +1/2 as at ^2
1) .v=u+at (derivation )
acceleration =change in velocity /time taken.
therefore, acceleration =(find velocity -initial velocity )/time taken.
hence , a=v-u/+or at =v-u
therefore, we have :v=u+at
2) .v^2=u^2+2 as (derivation )
distance (s)=((v+u)/2)×((v-u)/a)
s=(v^2-u^2)/2 as
2as=v^2-u^2
v^2=u^2+2 as
3).s=ut+1/2 at^2
distance =average velocity ×time;also ,
average velocity =(u+v)/2
therefore, distance (s)=(u+v)/2×t
from v=u at we have
s=(u +va +at)/2×t=(2u+at)/2×t
s=(2ut +at^2)/2=2ut/2+a^2/2
s=ut+1/2at^2.