Question

Write any 2 identities used in Factorisation.​

Answer 1

$\huge\blue{\boxed{\boxed{\mathcal{\bf\purple{♡}{\pink{Answer}\purple{♡}}}}}}$

(A + B)^2 = A^2 + 2AB + B^2

(A - B)^2 = A^2 - 2AB + B^2

Answer 2

Answer:

There are Four identities

$\sf \: 1) a² + 2ab +b² = (a + b)² \\ \sf \: 2) a² – 2ab + b² = (a – b)² \\ \sf 3) a² – b² = (a + b) (a – b) \\ \sf \: 4) x² + (a + b) x + ab = (x + a) (x + b)$

Step-by-step explanation:

$\green{ \text{Examples on 1st Identity of Factorization :}}$

1) 9a²+ 12ab + 4b²

$\bold{Solution}$

9a² + 12ab + 4b²

= (3a)² + 2 (3a) (2b) + (2b)²

= (3a + 2b)² [ since a = 3a and b = 2b; a 2 + 2ab + b 2 = (a + b) 2 ]

$\green {\text{Examples on 2nd Identity of Factorization :}}$

1) 4p² - 20pq + 25q²

$\bold{Solution :}$

4p² - 20pq + 25q²

= (2p)²- 2 (2p) (5q) + (5q)²

= (2p - 5q)² [ since a = 2p and b = 5q; a 2 + 2ab - b 2 = (a - b) 2 ]