Question

write any 5 molecular formula with steps​

Answer 1

Answer:

Suppose you are given a compound such as methyl acetate, a solvent commonly used in paints, inks, and adhesives. When methyl acetate was chemically analyzed, it was discovered to have 48.64% carbon (C), 8.16% hydrogen (H), and 43.20% oxygen (O). For the purposes of determining empirical formulas, we assume that we have 100 g of the compound. If this is the case, the percentages will be equal to the mass of each element in grams.

Step 1: Change each percentage to an expression of the mass of each element in grams. That is, 48.64% C becomes 48.64 g C, 8.16% H becomes 8.16 g H, and 43.20% O becomes 43.20 g O because we assume we have 100 g of the overall compound.

Step 2: Convert the amount of each element in grams to its amount in moles.

(48.64 g C1)(1 mol 12.01 g C)=4.049 mol

(8.16 g H1)(1 mol 1.008 g H)=8.095 mol

(43.20 g O1)(1 mol 16.00 g O)=2.7 mol

Step 3: Divide each of the mole values by the smallest of the mole values.

4.049 mol 2.7 mol =1.5

8.095 mol 2.7 mol =3

2.7 mol 2.7 mol =

Step 4: If necessary, multiply these numbers by integers in order to get whole numbers; if an operation is done to one of the numbers, it must be done to all of them.

1.5×2=3

3×2=6

1×2=2

Thus, the empirical formula of methyl acetate is C3H6O2.

Answer 2

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