write any four solutions for the equations. a. x + 2y = -5. b. 3x + y = 7. c. 3x + 5y = 15
Answers
Answer:-
Step-by-step explanation:
Answer:-
\begin{gathered}a)x + 2y = - 5 \\1st \: \: solution \: \\ x = 1 \\ \\ 1 + 2y = - 5 \\ \\ 2y = - 5 - 1 \\ \\ 2y = - 6 \\ \\ y = \frac{ - 6}{2} \\ \\ y = - 3 \\ 2nd \: \: \: solution \: \\ x = 2 \\ \\ 2 + 2y = - 5 \\ \\ 2y = - 7 \\ \\ y = \frac{ - 7}{2} \\ 3rd \: \: solution\\ x = 3 \\ \\ 3 + 2y = - 5 \\ \\ 2y = 8 \\ \\ y = - 4 \\ \\ 4th \: \: solution \\ \\ y = 1 \\ \\ x + 2 = - 5 \\ \\ x = - 7\end{gathered}
a)x+2y=−5
1stsolution
x=1
1+2y=−5
2y=−5−1
2y=−6
y=
2
−6
y=−3
2ndsolution
x=2
2+2y=−5
2y=−7
y=
2
−7
3rdsolution
x=3
3+2y=−5
2y=8
y=−4
4thsolution
y=1
x+2=−5
x=−7
\begin{gathered}b)3x + y = 7 \\ first \: \: solution\\ y = 1 \\ \\ 3x + 1 = 7 \\ \\ 3x = 6 \\ \\ x = 2 \\ 2 \: nd \: \: solution \: \\ \\ y = 2 \\ 3x + 2 = 7 \\ \\ 3x = 5 \\ \\ x = \frac{5}{3} \\ \\ 3rd \: \: solution \: \\ \\ y = 3 \\ \\ 3x + 3 = 7 \\ \\ 3x = 4 \\ \\ x = \frac{4}{3} \\ \\ 4th \: \: solution \\ \\ x = 1 \\ \\ 3 + y = 7 \\ \\ y = 4\end{gathered}
b)3x+y=7
firstsolution
y=1
3x+1=7
3x=6
x=2
2ndsolution
y=2
3x+2=7
3x=5
x=
3
5
3rdsolution
y=3
3x+3=7
3x=4
x=
3
4
4thsolution
x=1
3+y=7
y=4
\begin{gathered}c)3x + 5y = 15 \\ \\ 1 \: st \: \: solution \\ \\ x = 1 \\ \\ 3 + 5y = 15 \\ \\ 5y = 12 \\ \\ y = 12 \div 5 \\ \\ 2nd \: \: solution \\ \\ x = 2 \\ \\ 6 + 5y = 15 \\ \\ 5y = 9 \\ \\ y = 9 \div 5 \\ \\ 3rd \: \: solution \\ \\ y = 1 \\ \\ 3x + 5 = 15 \\ \\ 3x = 10 \\ \\ x = 10 \div 3 \\ \\ 4th \: \: solution \\ \\ y = 2 \\ \\ 3x + 10 = 15 \\ \\ 3x = 5 \\ \\ x = 5 \div 3\end{gathered}
c)3x+5y=15
1stsolution
x=1
3+5y=15
5y=12
y=12÷5
2ndsolution
x=2
6+5y=15
5y=9
y=9÷5
3rdsolution
y=1
3x+5=15
3x=10
x=10÷3
4thsolution
y=2
3x+10=15
3x=5
x=5÷3