write any four solutions of the following Linear Equations 3x-y=11
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4
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hence the four solutions are (4,1) (5,4) (6,7) (7,10)
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solution-1
let x=0
3×0-y=11
or, -y=11
or, y=11
Therefore, x=0,y=11
solution-2
let y=0
3x-0=11
x=11/3
therefore, x=11/3, y=11
solution-3
let x=1
3×1-y=11
3-y=11
-y=11-3
-y=8
y=-8
therefore, x=1,y=-8
solution-4
let y=1
3x-1=11
3x=11+1
x=12/3
x=4
therefore x=4,y=1
Thanks
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