write any three different solution of the linear equation 2x+3y=30
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4
Answer:
Step-by-step explanation:
let
1) x=0
then, 2(0)+3y=30
3y=30
y=(10)
2) y=0
then, 2x+3(0)=30
2x=30
x=15
3) x=6
then,2×6 +3y=30
12+3y=30
3y=30-12
3y=18
y=18/3
y=6
1) x,y=(0,10)
2) x,y=(15,0)
3) x,y=(6,6)
Answered by
1
2x+3y =30
x= 0 and y= 10
x= 15 and y= 0
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