Question

write any two no. whose sum is 13 and product is 40​

Answer 1

Answer:

6+8

4×10

Step-by-step explanation:

6+8=13

4×10=40

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Answer 2

Answer:

The two numbers are 5 and 8

Step-by-step explanation:

Let the two number be x and y

Then the sum of two numbers = x+y

And the product of two numbers = x×y

Now it is given that the sum of two numbers = 13

And the product of two numbers = 40

So, by given condition,

x+y = 13 and xy = 40 ------(2)

=> x = 13-y-----(1)

Now putting value of x in (2), we get,

(13-y) ×y = 40

=> 13y -y^2 = 40

=> y^2 -13y+40 = 0

=> y^2 -8y -5y +40 =0

=> (y-8) (y-5) = 0

=> y = 8,5

Now from (1), this implies, x = 13-y

So, when y = 8

Then x = 13-8 = 5

When, y=5

Then x = 13-5 = 8

So, The two numbers are 5 and 8