Question

write any two solutions of the equation 3x+4y=12​

Answer 1

Step-by-step explanation:

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x = 6, y =

2

−3

is the solution of the equation 3x + 4y - 12 = 0. If true enter 1 else 0.

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Solution

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Correct option is A)

Given equation: 3x + 4y - 12 = 0

⟹3x+4y=12

⟹4y=12−3x

⟹y=

4

12−3x

Check for x = 6 and y=

2

−3

for the solution of given equation:

We have, LHS = 3x + 4y - 12

⟹3x+4y=12

=3(6)+4(

2

−3

)−12

=18−6−12=0=RHS

Hence, x = 6 and y=

2

−3

is the solution of given equation.

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Answer 2

Step-by-step explanation:

From the question, we can see that 3x-4y =12 is an equation of two variables x and y. So, to find different points that lies on that line we have to assume anyone variable with some constant and then we will find the value of another variable.

At first, we will find different values of x by assuming the different values of y.

Let us assume that y=0.

Now, put y=0, in equation 3x – 4y =12 to find x.

⇒3x−4(0)=12

⇒3x=12

∴x=4

Now, let us assume that y=3.

Now, put y=3 in the equation 3x – 4y =12 to find x.

⇒3x−4(3)=12

⇒3x=24

∴x=8

Now, let us assume that y=-3

⇒3x−4(−3)=12

⇒3x=0

∴x=0

Now,

x 4 8 0

y 0 3 -3