Question

write as a+ib where z=3+root2i/1+i​

Answer 1

Step-by-step explanation:

$\sf{\underline{\underline{\large{\bold{Answer:-}}}}}$

$z = \frac{3 + \sqrt{2} i}{1 + i}$

$z = \frac{3 + \sqrt{2i} }{1 + i} \times \frac{ 3 - \sqrt{2i} }{3 - \sqrt{2i} }$

solve this u get urs answer

Answer 2

Answer:

Answer:−

z = \frac{3 + \sqrt{2} i}{1 + i}z=

1+i

3+

2

i

z = \frac{3 + \sqrt{2i} }{1 + i} \times \frac{ 3 - \sqrt{2i} }{3 - \sqrt{2i} }z=

1+i

3+

2i

×

3−

2i