Question

Write as a single fraction in its simplest form.

Answer 1

Answer:

-7x-1/x^2-1

Step-by-step explanation

 $\frac{x-2}{x+1}-\frac{x+3}{x-1}$

=$\frac{x-2}{x+1} *\frac{x-1}{x-1} -\frac{x+3}{x-1} *\frac{x+1}{x+1}$

=$\frac{(x-2)(x-1)}{x^2-1}- \frac{(x+3)(x+1)}{x^2-1}$

=$\frac{(x^2-x-2x+2)-(x^2+x+3x+3)}{x^2-1}$

=$\frac{x^2-3x+2-x^2-4x-3}{x^2-1}$

=$\frac{-7x-1}{x^2-1}$