Question

write as single logarithm 2log3-4log2+3log5​

Answer 1

Answer:

$2 log(3) - 4 log(2) + 3 log(5) \\ log( {3}^{2} ) - log( {2}^{4} ) + log( {5}^{3} ) \\ log(x) - log(y) = log( \frac{x}{y} ) \\ log(x) + log(y) = log(xy) \\ ( log( {3}^{2} ) - log( {2}^{4} ) ) = log( \frac{ {3}^{2} }{ {2}^{4} } ) \\ log( \frac{ {3}^{2} }{ {2}^{4} } ) + log( {5}^{3} ) = log (\frac{ {3}^{2} }{ {2}^{4} } \times {5}^{3} ) \\ log( \frac{9 \times 125}{16} ) = log( \frac{1125}{16} )$

Answer 2

Step-by-step explanation:

2log3 - 4log2 + 3log5

=log(3^2) - log(2^4) + log(5^3)

=log9 - log16 + log125

=log(9 × 125)/log16

=log(1125/16)

I think help you !!