Question

write ascending -3/7 , -3/2 ,-3/4​

Answer 1

$\huge{\underline{Question}}$ :-

→ write ascending -3/7 , -3/2 ,-3/4 .

$\huge{\underline{Answer}}$ :-

→ Firstly , make denominators of each fraction equal by taking LCM.

LCM ( 7, 2 , 4) = 28

$\therefore$ the new fraction formed will be :-

$\sf - \frac {3}{7} = - \frac {3}{7} \times \frac{4}{4} = - \frac{12}{28} \\ \\ \sf - \frac{3}{2} = - \frac{3}{2} \times \frac{14}{14} = - \frac{42}{28} \\ \\ \sf - \frac{3}{4} = - \frac{3}{4} \times \frac{7}{7} = - \frac{21}{28}$

so , observation :-

$\sf - \frac{42}{28} < - \frac{21}{28} < - \frac{12}{28}$

as fractions are negative, so greater negative Integers or fractions are smaller.

Hence , actual answer :-

$\sf - \frac{3}{2} < - \frac{3}{4} < - \frac{3}{7}$

Answer 2

$\huge\underline{\bold{\red{Answer\::}}}$

$\dfrac{-3}{7}$ , $\dfrac{-3}{2}$ , $\dfrac{-3}{4}$

We have to write them in ascending order.

To solve this we have to take LCM of 7, 2 and 4.

If we solve we get; 7 × 2 × 2

7 × 2 × 2 = 28

The LCM of all three numbers is 28.

⏩ $\dfrac{-3}{7}$ _(1)

As 7 × 4 = 28

So, we have to multiply eq (1) with 4 [both numerator and denominator]

$\dfrac{-3}{7}$ × $\dfrac{4}{4}$ = $\dfrac{-12}{28}$

⏩ $\dfrac{-3}{2}$ _(2)

As, 2 × 14 = 28

So, we have to multiply eq (2) with 14 [both numerator and denominator]

$\dfrac{-3}{2}$ × $\dfrac{14}{14}$ = $\dfrac{-42}{28}$

⏩ $\dfrac{-3}{4}$ _(3)

As, 4 × 7 = 28

So, we have to multiply eq (3) with 7 [both numerator and denominator]

$\dfrac{-3}{4}$ × $\dfrac{7}{7}$ = $\dfrac{-21}{28}$

Now we have to write that numbers in ascending order.

$\dfrac{-42}{28}$ < $\dfrac{-21}{28}$ < $\dfrac{-12}{28}$

So, the answer is..

$\dfrac{-3}{2}$ < $\dfrac{-3}{4}$ < $\dfrac{-3}{7}$