write atleast 10 numbers between 2000 to 2100 whose factors are 3,6,9
Answers
Answer:
3 = 2010, 2016, 2028, 2022, 2040, 2046, 2052, 2058, 2070, 2094
6 = 2010, 2016, 2028, 2022, 2040, 2046, 2052, 2058, 2070, 2094
9 = 2007, 2016, 2025, 2034, 2043, 2052, 2061, 2070, 2088, 2097
Step-by-step explanation:
3: (the sum of all the digits should be divisble by 3)
2010 — 2 + 0 + 1 + 0 = 3 ✓
2016 — 2 + 0 + 1 + 6 = 9 ✓
2022 — 2 + 0 + 2 + 2 = 6 ✓
2028 — 2 + 0 + 2 + 8 = 12 ✓
2040 — 2 + 0 + 4 + 0 = 6 ✓
2046 — 2 + 0 + 4 + 6 = 12 ✓
2052 — 2 + 0 + 5 + 2 = 9 ✓
2058 — 2 + 0 + 5 + 8 = 15 ✓
2070 — 2 + 0 + 7 + 0 = 9 ✓
2094 — 2 + 0 + 9 + 4 = 15 ✓
6: (should be divisible by 2 and 3)
2: (last digit should be divisible by 2)
2010 — 0 ✓
2016 — 6 ✓
2028 — 8 ✓
2022 — 2 ✓
2040 — 0 ✓
2046 — 6 ✓
2052 — 2 ✓
2058 — 8 ✓
2070 — 0 ✓
2094 — 4 ✓
9: (sum of all the digits should be divisible by 9)
2007 — 2 + 0 + 0 + 7 = 9 ✓
2016 — 2 + 0 + 1 + 6 = 9 ✓
2025 — 2 + 0 + 2 + 5 = 9 ✓
2034 — 2 + 0 + 3 + 4 = 9 ✓
2043 — 2 + 0 + 4 + 3 = 9 ✓
2052 — 2 + 0 + 5 + 2 = 9 ✓
2061 — 2 + 0 + 6 + 1 = 9 ✓
2070 — 2 + 0 + 7 + 0 = 9 ✓
2088 — 2 + 0 + 8 + 8 = 18 ✓
2097 — 2 + 0 + 9 + 7 = 18 ✓